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%TCIDATA{Created=Monday, December 11, 2006 20:01:13}
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\begin{document}


Determina el dominio de la funci\'{o}n $f(x)=\sqrt{\dfrac{x+3}{x-2}}$ 
\newline
\qquad a) $\left\{ x\in \mathbb{R}\mid x>2\right\} $\qquad b) $\left\{ x\in 
\mathbb{R}\mid x\neq 2\text{ }\right\} \bigskip $\newline
\qquad c) $\left\{ x\in \mathbb{R}\mid x>2\text{ y }x\neq -3\right\} $\qquad
d) $\left\{ x\in \mathbb{R}\mid x\neq 2\text{ y }x>-3\right\} $

Determina el dominio de la funci\'{o}n $f(x)=\dfrac{x+5}{\sqrt{x-4}}$ 
\newline
\qquad a) $\left\{ x\in \mathbb{R}\mid x>4\text{ }\right\} $\qquad b) $%
\left\{ x\in \mathbb{R}\mid x\neq 0\right\} \bigskip $\newline
\qquad c) $\left\{ x\in \mathbb{R}\mid x\geq 4\right\} $\qquad d) $\left\{
x\in \mathbb{R}\mid x\neq 4\right\} $

Determina el dominio de la funci\'{o}n $f(x)=\sqrt{\dfrac{x-1}{2x-5}}$ 
\newline
\qquad a) $\left\{ x\in \mathbb{R}\mid x>\frac{5}{2}\right\} $\qquad b) $%
\left\{ x\in \mathbb{R}\mid x\geq 1\text{ }\right\} \bigskip $\newline
\qquad c) $\left\{ x\in \mathbb{R}\mid x\geq \frac{5}{2}\right\} $\qquad d) $%
\left\{ x\in \mathbb{R}\mid x\neq \frac{5}{2}\right\} $

Determina el dominio de la funci\'{o}n $f(x)=\sqrt{\dfrac{x+1}{3x+1}}$ 
\newline
\qquad a) $\left\{ x\in \mathbb{R}\mid x>-\frac{1}{3}\text{ }\right\} $%
\qquad b) $\left\{ x\in \mathbb{R}\mid x\neq -1\right\} \bigskip $\newline
\qquad c) $\left\{ x\in \mathbb{R}\mid x\geq 0\right\} $\qquad d) $\left\{
x\in \mathbb{R}\mid \text{ }x\geq -1\right\} $

Determina el dominio de la funci\'{o}n $f(x)=\sqrt{\dfrac{2x-1}{3x-2}}$ 
\newline
\qquad a) $\left\{ x\in \mathbb{R}\mid \text{ }x>\frac{2}{3}\right\} $\qquad
b) $\left\{ x\in \mathbb{R}\mid x\geq \frac{1}{2}\text{ }\right\} $\bigskip 
\newline
\qquad c) $\left\{ x\in \mathbb{R}\mid x\neq \frac{1}{2}\right\} $\qquad d) $%
\left\{ x\in \mathbb{R}\mid x\geq \frac{2}{3}\right\} $

Determina el dominio de la funci\'{o}n $f(x)=\sqrt{\dfrac{5x+1}{x-3}}$ 
\newline
\qquad a) $\left\{ x\in \mathbb{R}\mid x>3\right\} $\qquad b) $\left\{ x\in 
\mathbb{R}\mid x\geq -\frac{1}{5}\right\} \bigskip $\newline
\qquad c) $\left\{ x\in \mathbb{R}\mid \text{ }x\neq 3\right\} $\qquad d) $%
\left\{ x\in \mathbb{R}\mid x\neq -\frac{1}{5}\right\} $

Determina el dominio de la funci\'{o}n $f(x)=\sqrt{\dfrac{2x-1}{x-3}}$%
\newline
\qquad a) $\left\{ x\in \mathbb{R}\mid x>3\right\} $\qquad b) $\left\{ x\in 
\mathbb{R}\mid x\geq \frac{1}{2}\text{ }\right\} \bigskip $\newline
\qquad c) $\left\{ x\in \mathbb{R}\mid x\geq 0\right\} $\qquad d) $\left\{
x\in \mathbb{R}\mid x\neq 3\right\} $

Determina el dominio de la funci\'{o}n $f(x)=\sqrt{\dfrac{3x-4}{4x-1}}$%
\newline
\qquad a) $\left\{ x\in \mathbb{R}\mid x\geq \frac{4}{3}\text{ }\right\} $ \
\ \ \ \ b) $\left\{ x\in \mathbb{R}\mid x\neq \frac{1}{4}\right\} $\bigskip 
\newline
\qquad c) $\left\{ x\in \mathbb{R}\mid x>\frac{1}{4}\right\} $\qquad d) $%
\left\{ x\in \mathbb{R}\mid \text{ }x>\frac{4}{3}\right\} $

Determina el dominio de la funci\'{o}n $f(x)=\sqrt{\dfrac{10-x}{2x-3}}$ 
\newline
\qquad a) $\left\{ x\in \mathbb{R}\mid \frac{3}{2}<x\leq 10\right\} $\qquad
b) $\left\{ x\in \mathbb{R}\mid x\geq 10\right\} $\bigskip \newline
\qquad c) $\left\{ x\in \mathbb{R}\mid x<\frac{3}{2}\text{ y }x\geq
10\right\} $\qquad d) $\left\{ x\in \mathbb{R}\mid x\neq \frac{3}{2}\right\} 
$

Determina el dominio de la funci\'{o}n $f(x)=\sqrt{\dfrac{2x-3}{8-x}}$ 
\newline
\qquad a) $\left\{ x\in \mathbb{R}\mid x<8\text{ y }x\geq \frac{3}{2}%
\right\} $\qquad b) $\left\{ x\in \mathbb{R}\mid x\geq \frac{3}{2}\text{ }%
\right\} $\newline
\qquad c) $\left\{ x\in \mathbb{R}\mid x\neq 8\right\} $\qquad d) $\left\{
x\in \mathbb{R}\mid x\geq 8\right\} $

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